Solved

Solve the Exponential Equation Algebraically 38x=24003 ^ { 8 x } = 2400

Question 38

Multiple Choice

Solve the exponential equation algebraically.Approximate the result to three decimal places.​ 38x=24003 ^ { 8 x } = 2400 ​


A) ln⁡24008ln⁡3≈0.018\frac { \ln 2400 } { 8 \ln 3 } \approx 0.018
B) ln⁡24008ln⁡3≈0.886\frac { \ln 2400 } { 8 \ln 3 } \approx 0.886
C) ln⁡24008ln⁡3≈0.089\frac { \ln 2400 } { 8 \ln 3 } \approx 0.089
D) ln⁡24008ln⁡3≈−0.886\frac { \ln 2400 } { 8 \ln 3 } \approx - 0.886
E) ln⁡24008ln⁡3≈1.248\frac { \ln 2400 } { 8 \ln 3 } \approx 1.248

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Q33: Solve the exponential equation algebraically.Approximate the

Q34: Solve the exponential equation algebraically.Approximate the

Q35: Solve the logarithmic equation algebraically.Approximate the

Q36: Solve for x.Approximate the result to

Q37: Solve the equation algebraically.Round the result

Q39: Solve the logarithmic equation algebraically.Approximate the

Q40: Solve the exponential equation algebraically.Approximate the

Q41: Solve for x: <span class="ql-formula"

Q42: Solve the exponential equation algebraically.Approximate the

Q43: Solve the exponential equation algebraically.Approximate the