Evaluate (if possible)the sine,cosine,and tangent of the real number.

t = \frac { 3 \pi } { 2 }

t = \frac { 3 \pi } { 2 }

corresponds to the point

( x , y ) = ( - 1,0 )

\begin{array} { l } \sin \left( \frac { 3 \pi } { 2 } \right) = 0 \\\\\cos \left( \frac { 3 \pi } { 2 } \right) = - 1 \\\\\tan \left( \frac { 3 \pi } { 2 } \right) = 0\end{array}

t = \frac { 3 \pi } { 2 }

corresponds to the point

( x , y ) = ( 0 , - 1 )

\begin{array} { l } \sin \left( \frac { 3 \pi } { 2 } \right) = - 1 \\\\\cos \left( \frac { 3 \pi } { 2 } \right) = 0\\\\\tan \left( \frac { 3 \pi } { 2 } \right)~ is~ undefined.\end{array}

t = \frac { 3 \pi } { 2 }

corresponds to the point

( x , y ) = ( 0,0 )

\begin{array} { l } \sin \left( \frac { 3 \pi } { 2 } \right) = 0 \\\\\cos \left( \frac { 3 \pi } { 2 } \right) = 0 \\\\\tan \left( \frac { 3 \pi } { 2 } \right) = 0\end{array}

t = \frac { 3 \pi } { 2 }

corresponds to the point

( x , y ) = ( - 1,0 )

\begin{array} { l } \sin \left( \frac { 3 \pi } { 2 } \right) = - 1 \\\\\cos \left( \frac { 3 \pi } { 2 } \right) = 0 \\\\\tan \left( \frac { 3 \pi } { 2 } \right) = 0\end{array}

E)Not possible

Find the Value of Given Trigonometric Function cos⁡(−2.5)\cos ( - 2.5 )cos(−2.5)

Multiple Choice