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Use the Trigonometric Substitution to Rewrite the Algebraic Expression as a Trigonometric

Question 6

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Use the trigonometric substitution to rewrite the algebraic expression as a trigonometric function of θ,where −π2<θ<π2- \frac { \pi } { 2 } < \theta < \frac { \pi } { 2 } .Then find sin θ and cos θ.​ 33=81−9x2,x=3cos⁡θ3 \sqrt { 3 } = \sqrt { 81 - 9 x ^ { 2 } } , x = 3 \cos \theta ​


A) ​ sin⁡θ=3;sin⁡θ=33;cos⁡θ=63\sin \theta = 3 ; \sin \theta = \frac { \sqrt { 3 } } { 3 } ; \cos \theta = \frac { \sqrt { 6 } } { 3 }
B) ​ 3sin⁡θ=3;sin⁡θ=0;cos⁡θ=13 \sin \theta = 3 ; \sin \theta = 0 ; \cos \theta = 1
C) ​ sin⁡θ=3;sin⁡θ=33;cos⁡θ=63\sin \theta = \sqrt { 3 } ; \sin \theta = \frac { \sqrt { 3 } } { 3 } ; \cos \theta = \frac { \sqrt { 6 } } { 3 }
D) ​ 9sin⁡θ=33;sin⁡θ=33;cos⁡θ=639 \sin \theta = 3 \sqrt { 3 } ; \sin \theta = \frac { \sqrt { 3 } } { 3 } ; \cos \theta = \frac { \sqrt { 6 } } { 3 }
E) ​ 3cos⁡θ=3;sin⁡θ=1;cos⁡θ=03 \cos \theta = 3 ; \sin \theta = 1 ; \cos \theta = 0

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