Use the Trigonometric Substitution to Rewrite the Algebraic Expression as a Trigonometric

Use the trigonometric substitution to rewrite the algebraic expression as a trigonometric function of θ,where $0 < x < \frac { \pi } { 2 }$ . $\sqrt { 6 - x ^ { 2 } } , x = \sqrt { 6 } \sin \theta$ ​

A) 6 sin θ
B) $- \sqrt { 6 } \cos \theta$
C) $\sqrt { 6 } \sin \theta$
D) $\sqrt { 6 } \cos \theta$
E) 6 cos θ

Correct Answer:

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