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Solve the Differential Equation with the Given Initial Condition y′=tan⁡tsec⁡2t;y(0)=1y ^ { \prime } = \tan t \sec ^ { 2 } t ; y ( 0 ) = 1

Question 48

Multiple Choice

Solve the differential equation with the given initial condition.
- y′=tan⁡tsec⁡2t;y(0) =1y ^ { \prime } = \tan t \sec ^ { 2 } t ; y ( 0 ) = 1


A) y = ln ∣tan⁡t∣| \tan \mathrm { t } | + 1
B) y = tan⁡2t2\frac { \tan ^ { 2 } \mathrm { t } } { 2 } + 1
C) y = tan t + 1
D) y = sec⁡2t3\frac { \sec ^ { 2 } t } { 3 } + 23\frac { 2 } { 3 }

Correct Answer:

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