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Given the Differential Equation y′=tsin⁡t2yy ^ { \prime } = \frac { t \sin t ^ { 2 } } { y }

Question 16

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Given the differential equation: y′=tsin⁡t2yy ^ { \prime } = \frac { t \sin t ^ { 2 } } { y } is this the solution y=±C−cos⁡t2?y = \pm \sqrt { C - \cos t ^ { 2 } } ?

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