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If Y = 3u + 2 and U = tt+1\frac { t } { t + 1 }

Question 26

Multiple Choice

If y = 3u + 2 and u = tt+1\frac { t } { t + 1 } , find dydt\frac { d y } { d t } .


A) 1(3u+2) 2\frac { 1 } { ( 3 u + 2 ) ^ { 2 } }
B) 19\frac { 1 } { 9 }
C) 1(t+1) 2\frac { 1 } { ( t + 1 ) ^ { 2 } }
D) 3(t+1) 2\frac { 3 } { ( t + 1 ) ^ { 2 } }

Correct Answer:

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