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Approximate ∫04\int _ { 0 } ^ { 4 } 1x2+1\frac { 1 } { x ^ { 2 } + 1 }

Question 122

Short Answer

Approximate ∫04\int _ { 0 } ^ { 4 } 1x2+1\frac { 1 } { x ^ { 2 } + 1 } dx; n = 2, by (a) the midpoint rule, (b) the trapezoidal rule, and (c) Simpson's rule.
Enter your answers in that order as just unlabeled real numbers rounded to two decimal places, separated by commas.

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