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The Density Function of a Normal Random Variable X Is f(x)=142πe−x2/32f ( x ) = \frac { 1 } { 4 \sqrt { 2 \pi } } e ^ { - x ^ { 2 } / 32 }

Question 9

Multiple Choice

The density function of a normal random variable X is f(x) =142πe−x2/32f ( x ) = \frac { 1 } { 4 \sqrt { 2 \pi } } e ^ { - x ^ { 2 } / 32 } Find the expected value E(X) E ( X )


A) 4
B) 0
C) 2
D) 8

Correct Answer:

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