Let $P ( x , y )$ Denote the Point Where the Terminal Side of Angle

Let $P ( x , y )$ denote the point where the terminal side of angle $\theta$ (in standard position) meets the unit circle. Use the information to evaluate the six trigonometric functions of $\theta$ . $P$ is in Quadrant IV and $y = - \frac { 3 } { 4 }$ .

A) $\sin \theta = - \frac { \sqrt { 7 } } { 4 }$ , $\cos \theta = \frac { 3 } { 4 }$ , $\tan \theta = - \frac { \sqrt { 7 } } { 3 }$ , $\sec \theta = \frac { 4 } { 3 }$ , $\csc \theta = \frac { 4 \sqrt { 7 } } { 7 }$ , $\cot \theta = \frac { 3 \sqrt { 7 } } { 7 }$
B) $\sin \theta = - \frac { \sqrt { 7 } } { 4 }$ , $\cos \theta = \frac { 3 } { 4 }$ , $\tan \theta = \frac { \sqrt { 7 } } { 3 }$ , $\sec \theta = \frac { 4 } { 3 }$ , $\csc \theta = - \frac { 4 \sqrt { 7 } } { 7 }$ , $\cot \theta = \frac { 3 \sqrt { 7 } } { 7 }$
C) $\sin \theta = - \frac { 3 } { 4 }$ , $\cos \theta = \frac { \sqrt { 7 } } { 4 }$ , $\tan \theta = - \frac { 3 \sqrt { 7 } } { 7 }$ , $\sec \theta = \frac { 4 \sqrt { 7 } } { 7 }$ , $\csc \theta = - \frac { 4 } { 3 }$ , $\cot \theta = - \frac { \sqrt { 7 } } { 3 }$
D) $\sin \theta = \frac { \sqrt { 7 } } { 4 } \quad \cos \theta = - \frac { 3 } { 4 } \quad \tan \theta = - \frac { \sqrt { 7 } } { 3 }$ $\sec \theta = \frac { 4 } { 3 }$ , $\csc \theta = \frac { \sqrt { 7 } } { 7 }$ , $\cot \theta = - \frac { \sqrt { 7 } } { 7 }$
E) $\sin \theta = \frac { 3 } { 4 }$ , $\cos \theta = - \frac { \sqrt { 7 } } { 4 }$ , $\tan \theta = \frac { 3 \sqrt { 7 } } { 7 }$ , $\sec \theta = - \frac { 4 \sqrt { 7 } } { 7 }$ , $\csc \theta = \frac { 4 } { 3 }$ , $\cot \theta = \frac { \sqrt { 7 } } { 3 }$

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