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    Principles of General Chemistry
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    Exam 23: Nuclear Reactions and Their Applications
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    Carbon-14 Will Emit A\(\beta\) Particle with an Energy of 0\(\times\)
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Carbon-14 Will Emit A β\betaβ Particle with an Energy of 0 ×\times×

Question 27

Question 27

Multiple Choice

Carbon-14 will emit a β\betaβ particle with an energy of 0.1565 MeV.What is this energy in joules?


A) 1.0 ×\times× 10-24 J
B) 2.5 ×\times× 10-20 J
C) 1.0 ×\times× 10-18 J
D) 2.5 ×\times× 10-14 J
E) None of these choices is correct.

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