Calculate the Standard Reaction Enthalpy for the Reaction $\rightarrow$ 2NH₃(g)
Given:
N₂H₄(l)+ O₂(g)

Calculate the standard reaction enthalpy for the reaction.
N₂H₄(l) + H₂(g) $\rightarrow$ 2NH₃(g)
Given:
N₂H₄(l) + O₂(g) $\rightarrow$ N₂(g) + 2H₂O(g)
$\Delta$ H° = -543 kJ.mol^-1
2H₂(g) + O₂(g) $\rightarrow$ 2H₂O(g)
$\Delta$ H° = -484 kJ.mol^-1
N₂(g) + 3H₂(g) $\rightarrow$ 2NH₃(g)
$\Delta$ H° = -92.2 kJ.mol^-1

A) (-935 kJ.mol^-1 )
B) (-1119 kJ.mol^-1 )
C) (-151 kJ.mol^-1 )
D) (-59 kJ.mol^-1 )
E) (-243 kJ.mol^-1 )

Correct Answer:

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