Solved

The Shortest Wavelength of a Photon That Can Be Emitted n=12,n = 12 ,

Question 26

Multiple Choice

The shortest wavelength of a photon that can be emitted by a hydrogen atom,for which the initial state is n=12,n = 12 , is closest to which one of the following values? (c=3.0×108 m/s,\left( c = 3.0 \times 10 ^ { 8 } \mathrm {~m} / \mathrm { s } , \right. h=6.626×10−34 J⋅sh = 6.626 \times 10 ^{- 34} \mathrm {~J} \cdot \mathrm { s } 1eV=1.60×10−19 J) 1 \mathrm { eV } = 1.60 \times 10^{ - 19} \mathrm {~J} )


A) 92 nm
B) 82 nm
C) 72 nm
D) 62 nm
E) 52 nm

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions