A 9-V Battery Is Hooked Up to Two Resistors in Series.One

A 9-V battery is hooked up to two resistors in series.One has a resistance of 5 Ω,and the other has a resistance of 10 Ω.Several locations along the circuit are marked with letters,as shown in the figure.Which resistor is converting electric energy into internal energy at the higher rate?

A) the 10-Ω resistor
B) the 5-Ω resistor
C) Energy is being dissipated by both resistors at the same rate.

Correct Answer:

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