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Write the Nuclear Equation for the Alpha Decay Of 22688\begin{array} { c } 226 \\88\end{array}

Question 71

Multiple Choice

Write the nuclear equation for the alpha decay of 22688\begin{array} { c } 226 \\88\end{array} Ra.


A) 88226Ra+24He→90230Th{ } _ { 88 } ^ { 226 } \mathrm { Ra } + { } _ { 2 } ^ { 4 } \mathrm { He } \rightarrow { } _ { 90 } ^ { 230 } \mathrm { Th }
B) 88226Ra→01n+88225Ra{ } _ { 88 } ^ { 226 } \mathrm { Ra } \rightarrow { } _ { 0 } ^ { 1 } \mathrm { n } + { } _ { 88 } ^ { 225 } \mathrm { Ra }
C) 88226Ra→−10e+89226Ac{ } _ { 88 } ^ { 226 } \mathrm { Ra } \rightarrow { } _ { - 1 } ^ { 0 } \mathrm { e } + { } _ { 89 } ^ { 226 } \mathrm { Ac }
D) 88226Ra++10e→89226Ac{ } _ { 88 } ^ { 226 } \mathrm { Ra } + { } _ { + 1 } ^ { 0 } \mathrm { e } \rightarrow { } _ { 89 } ^ { 226 } \mathrm { Ac }
E) 88226Ra→24He+86222Rn{ } _ { 88 } ^ { 226 } \mathrm { Ra } \rightarrow { } _ { 2 } ^ { 4 } \mathrm { He } + { } _ { 86 } ^ { 222 } \mathrm { Rn }

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