Calculate the Cell Potential for the Following Unbalanced Reaction That $\mathrm { Mg } ^ { 2 + }$

Calculate the cell potential for the following unbalanced reaction that takes place in an electrochemical cell at 25 °C when [ $\mathrm { Mg } ^ { 2 + }$ ] = 0.000612 M and [ $\mathrm { Fe } ^ { 3 + }$ ] = 1.29 M
$\quad$$\quad$ Mg(s) + $\mathrm { Fe } ^ { 3 + }$ (aq) ? $\mathrm { Mg } ^ { 2 + }$ (aq) + Fe(s)
E°(Mg²⁺/Mg) = -2.37 V and E°(Fe³⁺/Fe) = -0.036 V

A) -3.42 V
B) +3.42 V
C) -4.32 V
D) +2.43 V
E) +3.24 V

Correct Answer:

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