The Decomposition Of $\mathrm { N } _ { 2 }$

The decomposition of $\mathrm { N } _ { 2 }$ $\mathrm { O } _ { 5 }$ in solution in carbon tetrachloride proceeds via the reaction
2N₂O₅ (soln) ? $4 \mathrm { NO } _ { 2 }$ (soln) + $\mathrm { O } _ { 2 }$ (soln)
The reaction is first order and has a rate constant of 4.82 × $10 ^ { - 3 }$ $s ^ { - 1 }$ at 64 °C.If the reaction is initiated with 0.073 mol in a 1.00 L vessel,how many moles remain after 151 s?

A) 0.077 mol
B) 0.053 mol
C) 0.038 mol
D) 15 mol
E) 0.035 mol

Correct Answer:

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