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The Enthalpy Change for Converting 1  kJ. \text { kJ. } The Specific Heats of Ice,water,and Steam Are

Question 78

Multiple Choice

The enthalpy change for converting 1.00 mol of ice at -60.0°C to water at 80.0°C is ___________  kJ. \text { kJ. } The specific heats of ice,water,and steam are 2.09Jg−1∘C−12.09 \mathrm { Jg } ^ { - 1 } { } ^ { \circ } \mathrm { C } ^ { - 1 } 4.18Jg−1∘C−14.18 \mathrm { Jg } ^ { - 1 } { } ^ { \circ } \mathrm { C } ^ { - 1 } and 1.84Jg−1∘C−11.84 \mathrm { Jg } ^ { - 1 } { } ^ { \circ } \mathrm { C } ^ { - 1 } respectively.For H2\mathrm { H } _ { 2 } O, Δfus H\Delta _ { \text {fus } } H = 6.01 kJ mol-1,and Δvap H=40.67 kJ mol−1\Delta _ { \text {vap } } H = 40.67 \mathrm {~kJ} \mathrm {~mol} ^ { - 1 } .


A) 9.77
B) 14.29
C) 8282
D) 13.17
E) 48.95

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