Use the Data Given Below to Construct a Born-Haber Cycle

Use the data given below to construct a Born-Haber cycle to determine the second ionization energy of Ca.
$$\begin{array} { l c } & \Delta H ^ { \circ } \left( \mathrm { kJ } \mathrm { mol } ^ { - 1 } \right) \\\mathrm { Ca } ( s ) \rightarrow \mathrm { Ca } ( g ) & 193 \\\mathrm { Ca } ( g ) \rightarrow \mathrm { Ca } ^ { + } ( g ) + \mathrm { e } ^ { - } & 590 \\2 \mathrm { O } ( g ) \rightarrow \mathrm { O } _ { 2 } ( g ) & - 498 \\\mathrm { O } ( g ) + \mathrm { e } ^ { - } \rightarrow \mathrm { O } ^ { - } ( g ) & - 141 \\\mathrm { O } ^ { - } ( g ) + \mathrm { e } ^ { - } \rightarrow \mathrm { O } ^ { 2 - } ( g ) & 878 \\\mathrm { Ca } ( s ) + \frac { 1 } { 2 } \mathrm { O } _ { 2 } ( g ) \rightarrow \mathrm { CaO } ( s ) & - 635 \\\mathrm { Ca } ^ { 2 + } ( g ) + \mathrm { O } ^ { 2 - } ( g ) \rightarrow \mathrm { CaO } ( s ) & - 3414\end{array}$$

A) 1010 kJ mol^-1
B) 1757 kJ mol^-1
C) 1508 kJ mol^-1
D) -3027 kJ mol^-1
E) -1514 kJ mol^-1

Correct Answer:

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