Use the Data Given Below to Construct a Born-Haber Cycle

Use the data given below to construct a Born-Haber cycle to determine the lattice energy of CaO. $$\begin{array} { l r }& \Delta H ^ { \circ } \left( \mathrm { kJ } \mathrm { mol } ^ { - } 1 \right) \\ \mathrm { Ca } ( s ) \rightarrow \mathrm { Ca } ( g ) & 193 \\\mathrm { Ca } ( g ) \rightarrow \mathrm { Ca } ^ { + } ( g ) + \mathrm { e } ^ { - } &590 \\\mathrm { Ca } ^ { + } ( g ) \rightarrow \mathrm { Ca } ^ { + } ( g ) + \mathrm { e } ^ { - } &1010 \\2 \mathrm { O } ( g ) \rightarrow \mathrm { O } _ { 2 } ( g ) & - 498 \\\mathrm { O } ( g ) + \mathrm { e } ^ { - } \rightarrow \mathrm { O } ^ { - } ( g ) & - 141 \\\mathrm { O } ^ { - } ( g ) + \mathrm { e } ^ { - } \rightarrow \mathrm { O } ^ { 2 - } ( g ) & 878 \\\mathrm { Ca } ( s ) + \frac { 1 } { 2 } \mathrm { O } 2 ( g ) \rightarrow \mathrm { CaO } ( s ) & - 635\end{array}$$

A) -3414 kJ mol^-1
B) +1397 kJ mol^-1
C) -2667 kJ mol^-1
D) +3028 kJ mol^-1
E) -2144 kJ mol^-1

Correct Answer:

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