When 150 Mol of CH₄(g)reacts with Excess Cl₂(g)at Constant Pressure According

When 1.50 mol of CH₄(g) reacts with excess Cl₂(g) at constant pressure according to the chemical equation shown below,1062 kJ of heat are released.Calculate the value of ?H for this reaction,as written.
2CH₄(g) + 3Cl₂(g) ? 2CHCl₃(l) + 3H₂(g) $\Delta _ { \mathrm { r } }$ H° = ?

A) -1420 kJ $\mathrm { mol } ^ { - 1 }$
B) -708 kJ $\mathrm { mol } ^ { - 1 }$
C) +708 kJ $\mathrm { mol } ^ { - 1 }$
D) +1420 kJ $\mathrm { mol } ^ { - 1 }$

Correct Answer:

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Access For Free