Pure Acetic Acid $\mathrm { HC } _ { 2 }$

Pure acetic acid ( $\mathrm { HC } _ { 2 }$ $\mathrm { H } _ { 3 }$ $\mathrm { O } _ { 2 }$ ) is a liquid and is known as glacial acetic acid.Calculate the molarity of a solution prepared by dissolving 50.00 mL of glacial acetic acid at 25 °C in sufficient water to give 500.0 mL of solution.The density of glacial acetic acid at 25 °C is 1.05 g mL^-1.

A) 6.31 × 10³ mol L^-1
B) 105 mol L^-1
C) 0.105 mol L^-1
D) 1.75 × 10^-3 mol L^-1
E) 1.75 mol L^-1

Correct Answer:

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