When a Stationary Plutonium-239 $^{239}_{94}$ Pu, Decays into Uranium-235 Plus an Alpha Particle, the Energy

When a stationary plutonium-239, $^{239}_{94}$ Pu, decays into uranium-235 plus an alpha particle, the energy released in the process is 5.24 MeV. The following masses are known: $^{4}_{2}$ He: 4.002603 u $^{235}_{92}$ U: 235.043924 u What is the mass of the $^{239}_{94}$ Pu nucleus, in amu? (1 u = 931.494 MeV/c²)

A) 239.05215 u
B) 239.02775 u
C) 239.00189 u
D) 238.99919 u
E) 238.98884 u

Correct Answer:

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