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    Chemistry The Central Science Study Set 2
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    Exam 16: Acid-Base Equilibria
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    A- Is a Weak Base
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A- Is a Weak Base

Question 137

Question 137

Multiple Choice

A- is a weak base.Which equilibrium corresponds to the equilibrium constant Ka for HA?


A) HA (aq) + H2O (l) A- is a weak base.Which equilibrium corresponds to the equilibrium constant K<sub>a</sub> for HA? A) HA (aq) + H<sub>2</sub>O (l)    H<sub>2</sub>A<sup>+</sup><sup> </sup>(aq) + OH<sup>-</sup> (aq)  B) A<sup>-</sup> (aq) + H<sub>3</sub>O<sup>+</sup> (aq)    HA (aq) + H<sub>2</sub>O (l)  C) HA (aq) + H<sub>2</sub>O (l)    H<sub>3</sub>O<sup>+</sup> (aq) + A<sup>-</sup> (aq)  D) A<sup>-</sup> (aq) + H<sub>2</sub>O (l)    HA (aq) + OH<sup>-</sup> (aq)  E) A<sup>-</sup> (aq) + OH<sup>-</sup> (aq)    HOA<sup>2- </sup>(aq) H2A+ (aq) + OH- (aq)
B) A- (aq) + H3O+ (aq) A- is a weak base.Which equilibrium corresponds to the equilibrium constant K<sub>a</sub> for HA? A) HA (aq) + H<sub>2</sub>O (l)    H<sub>2</sub>A<sup>+</sup><sup> </sup>(aq) + OH<sup>-</sup> (aq)  B) A<sup>-</sup> (aq) + H<sub>3</sub>O<sup>+</sup> (aq)    HA (aq) + H<sub>2</sub>O (l)  C) HA (aq) + H<sub>2</sub>O (l)    H<sub>3</sub>O<sup>+</sup> (aq) + A<sup>-</sup> (aq)  D) A<sup>-</sup> (aq) + H<sub>2</sub>O (l)    HA (aq) + OH<sup>-</sup> (aq)  E) A<sup>-</sup> (aq) + OH<sup>-</sup> (aq)    HOA<sup>2- </sup>(aq) HA (aq) + H2O (l)
C) HA (aq) + H2O (l) A- is a weak base.Which equilibrium corresponds to the equilibrium constant K<sub>a</sub> for HA? A) HA (aq) + H<sub>2</sub>O (l)    H<sub>2</sub>A<sup>+</sup><sup> </sup>(aq) + OH<sup>-</sup> (aq)  B) A<sup>-</sup> (aq) + H<sub>3</sub>O<sup>+</sup> (aq)    HA (aq) + H<sub>2</sub>O (l)  C) HA (aq) + H<sub>2</sub>O (l)    H<sub>3</sub>O<sup>+</sup> (aq) + A<sup>-</sup> (aq)  D) A<sup>-</sup> (aq) + H<sub>2</sub>O (l)    HA (aq) + OH<sup>-</sup> (aq)  E) A<sup>-</sup> (aq) + OH<sup>-</sup> (aq)    HOA<sup>2- </sup>(aq) H3O+ (aq) + A- (aq)
D) A- (aq) + H2O (l) A- is a weak base.Which equilibrium corresponds to the equilibrium constant K<sub>a</sub> for HA? A) HA (aq) + H<sub>2</sub>O (l)    H<sub>2</sub>A<sup>+</sup><sup> </sup>(aq) + OH<sup>-</sup> (aq)  B) A<sup>-</sup> (aq) + H<sub>3</sub>O<sup>+</sup> (aq)    HA (aq) + H<sub>2</sub>O (l)  C) HA (aq) + H<sub>2</sub>O (l)    H<sub>3</sub>O<sup>+</sup> (aq) + A<sup>-</sup> (aq)  D) A<sup>-</sup> (aq) + H<sub>2</sub>O (l)    HA (aq) + OH<sup>-</sup> (aq)  E) A<sup>-</sup> (aq) + OH<sup>-</sup> (aq)    HOA<sup>2- </sup>(aq) HA (aq) + OH- (aq)
E) A- (aq) + OH- (aq) A- is a weak base.Which equilibrium corresponds to the equilibrium constant K<sub>a</sub> for HA? A) HA (aq) + H<sub>2</sub>O (l)    H<sub>2</sub>A<sup>+</sup><sup> </sup>(aq) + OH<sup>-</sup> (aq)  B) A<sup>-</sup> (aq) + H<sub>3</sub>O<sup>+</sup> (aq)    HA (aq) + H<sub>2</sub>O (l)  C) HA (aq) + H<sub>2</sub>O (l)    H<sub>3</sub>O<sup>+</sup> (aq) + A<sup>-</sup> (aq)  D) A<sup>-</sup> (aq) + H<sub>2</sub>O (l)    HA (aq) + OH<sup>-</sup> (aq)  E) A<sup>-</sup> (aq) + OH<sup>-</sup> (aq)    HOA<sup>2- </sup>(aq) HOA2- (aq)

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