For the Reaction 2SO 3 (g)$\rightarrow$ 2SO 2 (g)+ O 2 (g)$\Delta$ H r ° = +198 KJ$\Delta$

The Answer of For the Reaction 2SO 3 (g)$\rightarrow$ 2SO 2 (g)+ O 2 (g)$\Delta$ H r ° = +198 KJ$\Delta$

For the Reaction 2SO 3 (g)$\rightarrow$ 2SO 2 (g)+ O 2 (g)$\Delta$ H r ° = +198 KJ$\Delta$

The Answer of For the Reaction 2SO 3 (g)$\rightarrow$ 2SO 2 (g)+ O 2 (g)$\Delta$ H r ° = +198 KJ$\Delta$

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For the Reaction
2SO₃(g) $\rightarrow$ 2SO₂(g)+ O₂(g) $\Delta$ H_r° = +198 KJ $\Delta$

Question 158

Multiple Choice

For the reaction
2SO₃(g) $\rightarrow$ 2SO₂(g) + O₂(g)
$\Delta$ H_r° = +198 kJ.mol^-¹ and $\Delta$ S_r° = 190 J.K^-¹.mol^-¹ at 298 K.
The equilibrium constant for this reaction will be greater than 1 at

A) all temperatures.
B) temperatures above 1315 K.
C) temperatures below 1042 K.
D) no temperature.
E) temperatures above 1042 K.

For the Reaction 2SO3(g) →\rightarrow→ 2SO2(g)+ O2(g) Δ\DeltaΔ Hr° = +198 KJ Δ\DeltaΔ

Multiple Choice

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For the Reaction
2SO₃(g) $\rightarrow$ 2SO₂(g)+ O₂(g) $\Delta$ H_r° = +198 KJ $\Delta$

Correct Answer:
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