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Using the Born-Haber Cycle, the ΔHf° of KBr Is Equal

Question 28

Multiple Choice

Using the Born-Haber cycle, the ΔHf° of KBr is equal to __________.


A) ΔHf°[K (g) ] + ΔHf°[Br (g) ] + Il(K) + E(Br) + ΔHlattice
B) ΔHf°[K (g) ] - ΔHf°[Br (g) ] - Il(K) - E(Br) - ΔHlattice
C) ΔHf°[K (g) ] - ΔHf°[Br (g) ] + Il(K) - E(Br) + ΔHlattice
D) ΔHf°[K (g) ] + ΔHf°[Br (g) ] - Il - E(Br) + ΔHlattice
E) ΔHf°[K (g) ] + ΔHf°[Br (g) ] + Il(K) + E(Br) - ΔHlattice

Correct Answer:

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