Multiple Choice
The equilibrium constant expression for the reaction 2BrF5 (g)
Br2 (g) + 5F2 (g) is
A) Kc = [Br2] [F2] / [BrF5]
B) Kc = [Br2] [F2]5 / [BrF5]2
C) Kc = [Br2] [F2]2 / [BrF5]5
D) Kc = [BrF5]2 / [Br2][F2]5
E) Kc = 2[BrF5]2 / ([Br2] × 5[F2]5)
Correct Answer:

Verified
Correct Answer:
Verified
Q34: A reaction with an equilibrium constant K<sub>c</sub>
Q58: Consider the chemical reaction 2NH<sub>3</sub>(g) <img src="https://d2lvgg3v3hfg70.cloudfront.net/TB3246/.jpg"
Q59: The brown gas NO<sub>2</sub> and the colorless
Q60: A solution was prepared such that the
Q61: Consider the following equilibrium,<br>4NH<sub>3</sub>(g)+ 3O<sub>2</sub>(g) <img src="https://d2lvgg3v3hfg70.cloudfront.net/TB3246/.jpg"
Q62: At 400ºC, K<sub>c</sub> = 64 for the
Q64: Calculate K<sub>c</sub> for the reaction 2HI(g)<sub> </sub><sub>
Q65: Concerning the following reaction at equilibrium: 3Fe(s)+
Q67: The solubility of silver bromide can be
Q68: For the following reaction at equilibrium