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Determine E°cell for the Reaction: Pb(s)+ Cu2+(aq)→ Pb2+(aq)+ Cu(s)

Question 112

Multiple Choice

Determine E°cell for the reaction: Pb(s) + Cu2+(aq) → Pb2+(aq) + Cu(s) .The half reactions are:
Pb2+(aq) + 2 e- → Pb(s) E° = -0.125 V
Cu2+(aq) + 2 e- → Cu(s) E° = 0.340 V


A) 0.215 V
B) 0.465 V
C) 0.930 V
D) -0.215 V
E) -0.465 V

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