The Standard Enthalpy of Formation for CuSO₄ ∙ 5 H₂O(s)is

The standard enthalpy of formation for CuSO₄ ∙ 5 H₂O(s) is -2278.0 kJ/mol at 25 °C.The chemical equation to which this value applies is:

A) Cu(s) + S(s) + 5 H₂O(g) + 2 O₂(g) → CuSO₄ ∙ 5 H₂O(s)
B) Cu(s) + S(s) + 9/2 O₂(g) + 5 H₂(g) → CuSO₄ ∙ 5 H₂O(s)
C) Cu(s) + SO₄(g) + 5 H₂O(g) → CuSO₄ ∙ 5 H₂O(s)
D) Cu(s) + S(s) + 5/9 O₂(g) + 5 H₂(g) → CuSO₄ ∙ 5 H₂O(s)
E) 2 Cu(s) + 2 SO₂(g) + 5 H₂O(g) → 2 CuSO₄ ∙ 5 H₂O(s)

Correct Answer:

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Access For Free