Multiple Choice
Hydrogen iodide undergoes decomposition according to the equation
2HI(g) 
H2(g) + I2(g)
The equilibrium constant Kp at 500 K for this equilibrium is 0.060.Suppose 0.811 mol of HI is placed in a 1.50-L container at 500 K.What is the equilibrium concentration of H2(g) ?
(R = 0.0821 L ∙ atm/(K ∙ mol) )
A) 0.21 M
B) 0.13 M
C) 4.3 M
D) 0.039 M
E) 0.1 M
Correct Answer:
Verified
Correct Answer:
Verified
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