The Gas-Phase Decomposition of N₂O₅ Is a First-Order Process with a Rate

The gas-phase decomposition of N₂O₅ is a first-order process with a rate constant of 1.50 × 10^-3 s^-1 at 55°C.The decomposition reaction is
N₂O₅(g) → 2NO₂(g) +
O₂(g)
If 8.0 g of N₂O₅ is placed in vessel 1 and 16.0 g of N₂O₅ in vessel 2 and the vessels are at the same temperature (55°C) and the same pressure,how much time is required for half of the N₂O₅ to decompose in each vessel?

A) Vessel 1 requires the same amount of time as vessel 2.
B) Vessel 1 requires twice as much time as vessel 2.
C) Vessel 1 requires three times as much time as vessel 2.
D) Vessel 1 requires four times as much time as vessel 2.
E) Vessel 2 requires twice as much time as vessel 1.

Correct Answer:

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