For the Reaction CuS(s)+ H 2 (g)$\rarr$ H 2 S(g)+ Cu(s)$\Delta$ G° f (CuS)= -53$\Delta$

The Answer of For the Reaction CuS(s)+ H 2 (g)$\rarr$ H 2 S(g)+ Cu(s)$\Delta$ G° f (CuS)= -53$\Delta$

For the Reaction CuS(s)+ H 2 (g)$\rarr$ H 2 S(g)+ Cu(s)$\Delta$ G° f (CuS)= -53$\Delta$

The Answer of For the Reaction CuS(s)+ H 2 (g)$\rarr$ H 2 S(g)+ Cu(s)$\Delta$ G° f (CuS)= -53$\Delta$

Solved

For the Reaction CuS(s)+ H₂(g) $\rarr$ H₂S(g)+ Cu(s) $\Delta$ G°_f (CuS)= -53 $\Delta$

Question 98

Short Answer

For the reaction CuS(s)+ H₂(g) $\rarr$ H₂S(g)+ Cu(s),
$\Delta$ G°_f (CuS)= -53.6 kJ/mol
$\Delta$ G°_f (H₂S)= -33.6 kJ/mol
$\Delta$ H°_f (CuS)= -53.1 kJ/mol
$\Delta$ H°_f (H₂S)= -20.6 kJ/mol
Calculate the value of the equilibrium constant (K_p)at 798 K and 1 atm pressure.

For the Reaction CuS(s)+ H2(g) →\rarr→ H2S(g)+ Cu(s) Δ\DeltaΔ G°f (CuS)= -53 Δ\DeltaΔ

Short Answer

Correct Answer:VerifiedUnlock this answer nowGet Access to more Verified Answers free of chargeAccess For Free

For the Reaction CuS(s)+ H₂(g) $\rarr$ H₂S(g)+ Cu(s) $\Delta$ G°_f (CuS)= -53 $\Delta$

Correct Answer:
Verified
Unlock this answer now
Get Access to more Verified Answers free of charge