For the Reaction CuS(s)+ H 2 (g)$\rarr$ H 2 S(g)+ Cu(s)$\Delta$ G° f (CuS)= -53$\Delta$

The Answer of For the Reaction CuS(s)+ H 2 (g)$\rarr$ H 2 S(g)+ Cu(s)$\Delta$ G° f (CuS)= -53$\Delta$

For the Reaction CuS(s)+ H 2 (g)$\rarr$ H 2 S(g)+ Cu(s)$\Delta$ G° f (CuS)= -53$\Delta$

The Answer of For the Reaction CuS(s)+ H 2 (g)$\rarr$ H 2 S(g)+ Cu(s)$\Delta$ G° f (CuS)= -53$\Delta$

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For the Reaction CuS(s)+ H₂(g) $\rarr$ H₂S(g)+ Cu(s) $\Delta$ G°_f (CuS)= -53 $\Delta$

Question 45

Short Answer

For the reaction CuS(s)+ H₂(g) $\rarr$ H₂S(g)+ Cu(s),
$\Delta$ G°_f (CuS)= -53.6 kJ/mol
$\Delta$ G°_f (H₂S)= -33.6 kJ/mol
$\Delta$ H°_f (CuS)= -53.1 kJ/mol
$\Delta$ H°_f (H₂S)= -20.6 kJ/mol
Calculate $\Delta$ G at 798 K and 1 atm pressure (assume $\Delta$ S°and $\Delta$ H° do not change with temperature).

For the Reaction CuS(s)+ H2(g) →\rarr→ H2S(g)+ Cu(s) Δ\DeltaΔ G°f (CuS)= -53 Δ\DeltaΔ

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For the Reaction CuS(s)+ H₂(g) $\rarr$ H₂S(g)+ Cu(s) $\Delta$ G°_f (CuS)= -53 $\Delta$

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