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For the Reaction CuS(s)+ H2(g) →\rarr H2S(g)+ Cu(s) Δ\Delta G°f (CuS)= -53 Δ\Delta

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For the reaction CuS(s)+ H2(g) →\rarr H2S(g)+ Cu(s),
Δ\Delta G°f (CuS)= -53.6 kJ/mol
Δ\Delta G°f (H2S)= -33.6 kJ/mol
Δ\Delta H°f (CuS)= -53.1 kJ/mol
Δ\Delta H°f (H2S)= -20.6 kJ/mol
Calculate the value of the equilibrium constant (Kp)for this reaction at 298 K.

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3.11 * 10<...

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