Short Answer
Ethanol and acetic acid react to form ethyl acetate and water according to the following chemical equation:
C2H5OH(l)+ CH3COOH(l) ![Ethanol and acetic acid react to form ethyl acetate and water according to the following chemical equation: C<sub>2</sub>H<sub>5</sub>OH(l)+ CH<sub>3</sub>COOH(l) CH<sub>3</sub>COOC<sub>2</sub>H<sub>5</sub>(l)+ H<sub>2</sub>O(l) When two moles each of ethanol and acetic acid are combined, equilibrium is reached when two-thirds of a mole of each of the reactants remains. Calculate the equilibrium constant for this reaction assuming total volume does not change during the course of the reaction. (Note: since water is not the solvent, but rather a product of the reaction, [H<sub>2</sub>O] changes during the course of the reaction, so it should be included in the equilibrium constant expression.)](https://d2lvgg3v3hfg70.cloudfront.net/TB3244/11ea7995_6663_6851_911b_1f4b8d143e02_TB3244_00.jpg)
CH3COOC2H5(l)+ H2O(l)
When two moles each of ethanol and acetic acid are combined, equilibrium is reached when two-thirds of a mole of each of the reactants remains. Calculate the equilibrium constant for this reaction assuming total volume does not change during the course of the reaction. (Note: since water is not the solvent, but rather a product of the reaction, [H2O] changes during the course of the reaction, so it should be included in the equilibrium constant expression.)
Correct Answer:
Verified
Correct Answer:
Verified
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