A 100 Gram Glass Container Contains 200 Grams of Water $^{\circ}$

A 100 gram glass container contains 200 grams of water and 100 grams of ice all at 0 $^{\circ}$ C.A 200 gram piece of lead at 100 $^{\circ}$ C is added to the water and ice in the container.What is the final temperature of the system? (specific heat of ice = 2,000 J/kg $^{\circ}$ C ,specific heat of water = 4,186 J/kg $^{\circ}$ C,heat of fusion of water = 333.7 kJ/kg,specific heat of glass = 837.2 J/km $^{\circ}$ C,specific heat of lead = 127.7 J/km $^{\circ}$ C)

A) 1.85 $^{\circ}$ C
B) 2.04 $^{\circ}$ C
C) 2.86 $^{\circ}$ C
D) 3.43 $^{\circ}$ C
E) 4.01 $^{\circ}$ C

Correct Answer:

Verified

Show Answer