Multiple Choice
When using reductio ad absurdum to prove (x) Fx ⋁ ($x) Gx, we begin by assuming
A) ~(x) Fx ⋁ ($x) Gx.
B) (x) Fx.
C) ~((x) Fx ⋁ ($x) Gx) .
D) (x) Fx • ~($x) Gx.
Correct Answer:

Verified
Correct Answer:
Verified
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