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The Absolute Minimum of the Function f(x)=8x3−4x2+72xf ( x ) = 8 x ^ { 3 } - 4 x ^ { 2 } + 72 x

Question 83

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The absolute minimum of the function f(x)=8x3−4x2+72xf ( x ) = 8 x ^ { 3 } - 4 x ^ { 2 } + 72 x on the interval 0 ≤\le x ≤\le 4 is 0.

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