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If x3+y3=x+yx ^ { 3 } + y ^ { 3 } = x + y

Question 87

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If x3+y3=x+yx ^ { 3 } + y ^ { 3 } = x + y , then dydx=3x2−13y2−1\frac { d y } { d x } = \frac { 3 x ^ { 2 } - 1 } { 3 y ^ { 2 } - 1 } .

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