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If 12A=2Ae−0.06x\frac { 1 } { 2 } A = 2 A e ^ { - 0.06 x }

Question 14

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If 12A=2Ae−0.06x\frac { 1 } { 2 } A = 2 A e ^ { - 0.06 x } , then x is ln⁡40.06\frac { \ln 4 } { 0.06 } .

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