Solved

Consider a Reaction Given By
-In the Same Mechanism, the Faradaic Impedance (ZF) Is

Question 7

Multiple Choice

Consider a reaction given by M⇄k1k−1Mads++e−Mads+⇄k2k−2Msol+\begin{array} { l } M \underset { k _ { - 1 } } { \stackrel { k _ { 1 } } { \rightleftarrows } } M _ { a ds } ^ { + } + e ^ { - } \\M _ { a d s } ^ { + }\underset { k _ { - 2 } } { \stackrel { k _ { 2 } } { \rightleftarrows } } M _ { sol } ^ { + }\end{array} .
-In the same mechanism, the faradaic impedance (ZF) is given by


A) (ZF) −1=F(b1k1dc˙(1−θss) −b−1k−1α˙θss+(k1dc˙+k−1dc˙+k2) dθdE) \left( Z _ { F } \right) ^ { - 1 } = F \left( b _ { 1 } k _ { 1 \dot { dc } } \left( 1 - \theta _ { s s } \right) - b _ { - 1 } k _ { - 1 \dot { \alpha } } \theta _ { ss } + \left( k _ { 1 \dot { dc } } + k _ { - 1 \dot { dc } } + k _ { 2 } \right) \frac { d \theta } { d E } \right)
B) (ZF) −1=F(b1k1dc˙(1−θss) −b−1k−1˙θss−(k1dc˙+k−1dc˙+k2) dθdE) \left( Z _ { F } \right) ^ { - 1 } = F \left( b _ { 1 } k _ { 1 d \dot { c } } \left( 1 - \theta _ { s s } \right) - b _ { - 1 } k _ { - 1 \dot { } } \theta _ { s s } - \left( k _ { 1 \dot { dc } } + k _ { - 1 \dot {dc } } + k _ { 2 } \right) \frac { d \theta } { d E } \right)
C) (ZF) −1=F(b1k1dc˙(1−θss) −b−1k−1dc˙θss−(k1dc˙+k−1dc˙) dθdE) \left( Z _ { F } \right) ^ { - 1 } = F \left( b _ { 1 } k _ { 1 \dot { dc } } \left( 1 - \theta _ { s s } \right) - b _ { - 1 } k _ { - 1 \dot {dc } } \theta _ { s s } - \left( k _ { 1 d \dot {c } } + k _ { - 1 \dot { dc } } \right) \frac { d \theta } { d E } \right)
D) (ZF) −1=F(b1k1dc˙(1−θss) −b−1k−1dc˙θss+(k1dc˙+k−1dc˙) dθdE) \left( Z _ { F } \right) ^ { - 1 } = F \left( b _ { 1 } k _ { 1 d \dot { c} } \left( 1 - \theta _ { s s } \right) - b _ { - 1 } k _ { - 1 \dot { dc } } \theta _ { ss } + \left( k _ { 1 d \dot { c} } + k _ { - 1 d \dot {c } } \right) \frac { d \theta } { d E } \right)

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions