Multiple Choice
Passage
Fluorescent amino acids are useful for labeling proteins because they can be visualized spectroscopically, facilitating the study of protein structure and interactions. The noncanonical amino acid dansylalanine, a fluorescent amino acid that is sensitive to the hydrophobicity of its environment, is a good candidate to be incorporated into proteins because of its small size and fluorescent capabilities. Dansyl chloride and Compound 1 were used to synthesize dansylalanine, as shown in Reaction 1. Dansylalanine absorbs maximally at 340 nm and emits at approximately 540 nm.
Reaction 1 Synthesis of dansylalanineA leucyl-tRNA synthetase from Escherichia coli was engineered to aminoacylate bacterial tRNAs containing a CUA anticodon with dansylalanine. After verifying that the tRNA/synthetase pair does not interact with endogenous amino acids or tRNAs, it was transfected into the yeast Saccharomyces cerevisiae along with a plasmid encoding a mutated human superoxide dismutase (hSOD) . Using this system, dansylalanine was genetically incorporated into hSOD in place of either Gln-16 or Trp-33, and expressed in S. cerevisiae.Position 16 is located on the surface of hSOD at the N-terminus of a β-strand, and position 33 lies in the center of a strand within a β-barrel. To probe changes in the structure of hSOD, researchers exposed the purified protein to guanidinium chloride (GdmCl) to denature the protein at concentrations ranging 0-4.5 M. The experiment was conducted in a 35 mM sodium phosphate buffer at pH 7.2. The fluorescence of hSOD with dansylalanine at either position 16 or 33 was monitored at each GdmCl concentration, and the results of the unfolding experiment are shown in Figure 1.
Figure 1 Plot of dansylalanine fluorescence at different concentrations of GdmCl
Adapted from Summerer D, Chen S, Wu N, Deiters A, Chin JW, Schultz PG. A genetically encoded fluorescent amino acid. Proc Natl Acad Sci USA. 2006.
-What is the charge of the N-terminus during the protein unfolding experiment?
A) +1, because the amine group is not protonated
B) +1, because the amine group is in the conjugate acid form
C) 0, because the amine group is protonated
D) 0, because the amine group is in the conjugate base form
Correct Answer:

Verified
Correct Answer:
Verified
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