Solve the System by the Substitution or Elimination Method$$\left( \begin{array} { r l }
2 x^{2}-3 y^{2}=-1 \
2 x^{2}+3 y^{2}=5
\end{array} \right)$$

Question

Solve the System by the Substitution or Elimination Method$$\left( \begin{array} { r l } 
2 x^{2}-3 y^{2}=-1 \
2 x^{2}+3 y^{2}=5
\end{array} \right)$$

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The Answer of Solve the System by the Substitution or Elimination Method$$\left( \begin{array} { r l } 
2 x^{2}-3 y^{2}=-1 \
2 x^{2}+3 y^{2}=5
\end{array} \right)$$

Solve the System by the Substitution or Elimination Method $\left( \begin{array} { r l } 2 x^{2}-3 y^{2}=-1 \\2 x^{2}+3 y^{2}=5\end{array} \right)$

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Solve the System by the Substitution or Elimination Method (2x2−3y2=−12x2+3y2=5)\left( \begin{array} { r l } 2 x^{2}-3 y^{2}=-1 \\2 x^{2}+3 y^{2}=5\end{array} \right)(2x2−3y2=−12x2+3y2=5​)

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Solve the System by the Substitution or Elimination Method $\left( \begin{array} { r l } 2 x^{2}-3 y^{2}=-1 \\2 x^{2}+3 y^{2}=5\end{array} \right)$

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