Three Blue Marbles, Eight Green Marbles, and Seven Red Marbles $\frac { 7 } { 36 }$

Three blue marbles, eight green marbles, and seven red marbles are placed in a bag. One marble is chosen at random.
a. What is the probability that the marble chosen is red?
b. Which is greater, the probability of choosing a blue marble or that of choosing a red marble?

A) (a) $\frac { 7 } { 36 }$ ; (b) Choosing a red marble
B) (a) $\frac { 7 } { 36 }$ ; (b) Neither
C) (a) $\frac { 7 } { 18 }$ ; (b) Choosing a blue marble
D) (a) $\frac { 7 } { 18 }$ ; (b) Choosing a red marble
E) (a) $\frac { 7 } { 36 }$ ; (b) Choosing a blue marble

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