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Solve the Differential Equation Using the Method of Variation of Parameters

Question 52

Multiple Choice

Solve the differential equation using the method of variation of parameters. ytt−4yt+3y=2sin⁡xy ^ { tt } - 4 y ^ {t } + 3 y = 2 \sin x


A) y(x) =c1e3x+c2ex+15sin⁡xy ( x ) = c _ { 1 } e ^ { 3 x } + c _ { 2 } e ^ { x } + \frac { 1 } { 5 } \sin x
B) y(x) =c1e3x+c2ex+25cos⁡x+15sin⁡xy ( x ) = c _ { 1 } e ^ { 3 x } + c _ { 2 } e ^ { x } + \frac { 2 } { 5 } \cos x + \frac { 1 } { 5 } \sin x
C) y(x) =c1sin⁡x+c25x+15sin⁡xy ( x ) = c _ { 1 } \sin x + \frac { c _ { 2 } } { 5 } x + \frac { 1 } { 5 } \sin x
D) y(x) =c1sin⁡3x+c24x+cos⁡3xy ( x ) = c _ { 1 } \sin 3 x + \frac { c _ { 2 } } { 4 } x + \cos 3 x
E) y(x) =c1e3x+c2ex+25sin⁡xy ( x ) = c _ { 1 } e ^ { 3 x } + c _ { 2 } e ^ { x } + \frac { 2 } { 5 } \sin x

Correct Answer:

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