Find the Integral Using an Appropriate Trigonometric Substitution $$\int x \sqrt { 9 - x ^ { 2 } } d x$$

Find the integral using an appropriate trigonometric substitution. $$\int x \sqrt { 9 - x ^ { 2 } } d x$$

A) $\frac { 1 } { 3 } x ^ { 2 } \left( 9 - x ^ { 2 } \right) ^ { 3 / 2 } + C$
B) $- \frac { 1 } { 3 } \left( 9 - x ^ { 2 } \right) ^ { 3 / 2 } + C$
C) $- \frac { 1 } { 3 } x ^ { 2 } \left( 9 - x ^ { 2 } \right) ^ { 3 / 2 } + C$
D) $\frac { 1 } { 3 } \left( 9 - x ^ { 2 } \right) ^ { 3 / 2 } + C$

Correct Answer:

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Access For Free