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  2. Topic
    Mathematics
  3. Study Set
    Calculus International
  4. Exam
    Exam 4: Applications of Differentiation
  5. Question
    Find the General Indefinite Integral\[\int \frac { \sin 18 t } { \sin 9 t } d t\]
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Find the General Indefinite Integral ∫sin⁡18tsin⁡9tdt\int \frac { \sin 18 t } { \sin 9 t } d t∫sin9tsin18t​dt

Question 30

Question 30

Short Answer

Find the general indefinite integral. ∫sin⁡18tsin⁡9tdt\int \frac { \sin 18 t } { \sin 9 t } d t∫sin9tsin18t​dt

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