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Evaluate the Integral Using an Appropriate Trigonometric Substitution ∫02x24−x2dx\int _ { 0 } ^ { \sqrt { 2 } } \frac { x ^ { 2 } } { \sqrt { 4 - x ^ { 2 } } } d x

Question 60

Multiple Choice

Evaluate the integral using an appropriate trigonometric substitution. ∫02x24−x2dx\int _ { 0 } ^ { \sqrt { 2 } } \frac { x ^ { 2 } } { \sqrt { 4 - x ^ { 2 } } } d x


A) π−1\pi - 1
B) π\pi
C) 2π3−32\frac { 2 \pi } { 3 } - \frac { \sqrt { 3 } } { 2 }
D) π2−1\frac { \pi } { 2 } - 1

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