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Solve the Initial-Value Problem xyt=y+x2cos⁡x,y(π)=0x y ^ { t } = y + x ^ { 2 } \cos x , y ( \pi ) = 0

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Solve the initial-value problem. xyt=y+x2cos⁡x,y(π)=0x y ^ { t } = y + x ^ { 2 } \cos x , y ( \pi ) = 0

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