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Find the (X,y) Pair for the Value of the Parameter x=∣t+1∣x = | t + 1 |

Question 33

Multiple Choice

Find the (x,y) pair for the value of the parameter.
- x=∣t+1∣x = | t + 1 | and y=1t2y = \frac { 1 } { t ^ { 2 } } for t=2t = 2


A) (3,14) \left( 3 , \frac { 1 } { 4 } \right)
B) (−3,14) \left( - 3 , \frac { 1 } { 4 } \right)
C) (14,−3) \left( \frac { 1 } { 4 } , - 3 \right)
D) (1,14) \left( 1 , \frac { 1 } { 4 } \right)

Correct Answer:

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